0=16t^2+4t+1

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Solution for 0=16t^2+4t+1 equation: 



0=16t^2+4t+1

We move all terms to the left:

0-(16t^2+4t+1)=0

We add all the numbers together, and all the variables

-(16t^2+4t+1)=0

We get rid of parentheses

-16t^2-4t-1=0

a = -16; b = -4; c = -1;
Δ = b2-4ac
Δ = -42-4·(-16)·(-1)
Δ = -48
Delta is less than zero, so there is no solution for the equation

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